A stone was dropped off a cliff and hit the ground with a speed of 112 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)

Answer 1

s = 1/2 at^2
v = at, so t = v/a

s = 1/2 a(v^2/a^2) = 1/2 v^2/a = 112^2/64 = 196 ft