centripetal acceleration
a= mv²/R=
=0.05•4/0.5=0.4 m/s²
a stone of mass 50g is being rotated in a circle of radius 50cm with a uniform speed of 2m/s.what is thje accelerationof the stone?
2 answers
centripetal acceleration
a= v²/R=
= 4/0.5=8 m/s²
centripetal force
F= mv²/R=
=0.05•4/0.5=0.4 m/s²
a= v²/R=
= 4/0.5=8 m/s²
centripetal force
F= mv²/R=
=0.05•4/0.5=0.4 m/s²