A stone of mass 0.7kg is projected vertically upward with a speed of 5m/s.calculate the maximum height reached. [Take g=10m/s^2 and neglect air resistance].
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4 answers
V^2 = Vo^2 + 2g*h, V = 0, Vo = 5m/s, g = -10m/s^2, h = ?.
a baseball is thrown vertically upward with an initial speed of 20m/s .calculate how fast it was travelling on its way down when caught 5.0m above where it was thrown.
2.8
The appropriate formular is..
H=u(square)/2g..
height=U square(initial vel.) /divided by 2g
so,_H=5sqr /2*10.
Therefore;-25 /20..which is equare to 1.25m. ans(1.25 m).
H=u(square)/2g..
height=U square(initial vel.) /divided by 2g
so,_H=5sqr /2*10.
Therefore;-25 /20..which is equare to 1.25m. ans(1.25 m).
0 answers