A stone of 5g is stretched through aDistanc of 7cm by an average force if 70N calculay the velocity of the stone when releasedf

Answer 1

First, calculate the work done on the stone by the force:

Work = force x distance
Work = 70N x 0.07m
Work = 4.9 J

Next, calculate the kinetic energy of the stone when released:

Kinetic energy = 1/2 x mass x velocity^2
4.9 J = 1/2 x 5g x velocity^2
4.9 J = 0.0025 kg x velocity^2
velocity^2 = 1960 m^2/s^2

Finally, calculate the velocity of the stone when released:

velocity = sqrt(1960 m^2/s^2)
velocity ≈ 44.3 m/s

Therefore, the velocity of the stone when released is approximately 44.3 m/s.