A stone is thrown vertically upward at a speed of 30.30 m/s at time t=0. A second stone is thrown upward with the same speed 2.500 seconds later. At what time are the two stones at the same height?

Answer 1

At what height do the two stones pass each other?

What is the upward speed of the second stone as they pass each other?

Answer 2

when
30.30t - 4.9t^2 = 30.30(t-2.5) - 4.9(t-2.5)^2
now just solve for t.