A stone is thrown straight up with a velocity of 24.0m/s from a height of 2.00m. How fast is it moving when it is at a height of 13.0m? How much time is required to reach this height?

Answer 1

13 = -½ g t² + 24 t + 2

solve for t...there will be two solutions (up and down)

the velocity is...v = 24 - g t
...use the up (smaller) time

Answer 2

a. V^2 = Vo^2 + 2g*h = 24^2 - 19.6 *(13-2) =

b. V = Vo + g*t. V = (part a), Vo = 24 m/s, g = -9.8m/s^2, t = ?.