A stone is thrown straight up and reaches a maximum height of 26 m. With what speed was the stone thrown?

2 answers

V^2 = Vo^2 + 2g*h
V = 0 @ max h.
g = -9.8 m/s^2.
h = 26 m.
Vo = ? (m/s).
V(initial)=*2(g)(h)*
**<--- substitute for a square root symbol

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