A stone is thrown from ground level at 84 m/s. It's speed when it reaches it's highest point is 50 m/s. Find the angle, above the horizontal, of the stones initial velocity.

2 answers

v(x) =v₀(x) = 50 m/s
v₀=84 m/s
cosα =v₀(x)/ v₀=50/84 =0.6
α=53.5⁰
how did you get 53.5