y = tanθ x - g/(2 (v cosθ)^2) x^2
so plug in your numbers and solve for v when
y(10) = 2
a stone is thrown at an angle of 30* with the horizontal direction which strikes the tip of the building 2 m height ,if the distance of the building from the point of observation is 10 metre .find the velocity of the projectile of the stone.
1 answer