the horizontal component of the stone's velocity is
...12 m/s * cos(30º)
multiply by 8 s to find the distance
a stone is thrown at an angle of 30 degrees above the horizontal from the top edge of a cliff with an initial speed of 12m/s. a stop watch measures the stone's trajectory time from top of cliff to bottom to be 8s. how far out from the cliff's edge does the stone travel horizontally? (air resistance is negligible)
1 answer
1 answer