A stone is thrown 60 degrees below the horizontal at 22 ft/sec and 20 meters above the ground. Using the energy equations, determine its velocity when it hits the ground.

Answer 1

Are you sure the stone was thrown at an angle below the horizontal? If so,

h(t) = 20 - (22*sin60)t - 4.9t^2
solve for t when h=0.

the vertical speed is -22*sin60 - 9.8t
the horizontal speed is a constant 22*cos60

so, knowing the final components of the velocity, you can figure its magnitude and direction.

Answer 2

ft/sec?
If it is you need to convert as well.