a stone is from the top of a tower 300m high and at the same time another stone is projected vertically upward with initial velocity 75m/s. calculate when and where the two stone meet

Answer 1

Solve for the t when
first stone height = second stone height
300 - 4.9 t^2 = 75 t- 4.9 t^2

The "4.9" is g/2, in m/s^2

75 t = 300
t = 4 seconds
height = 300 - 4.9*16 = 226 m