A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well. (Remember acceleration is -9.80 m/s

Answer 1

Given:
Time taken for the stone to hit the water, t = 3.41 s
Acceleration due to gravity, g = -9.80 m/s^2

Using the equation of motion:
d = (1/2)gt^2

Substitute the given values:
d = (1/2)(-9.80)(3.41)^2
d = (1/2)(-9.80)(11.6281)
d = (-4.9)(11.6281)
d = -56.90439

Since distance cannot be negative, we take the absolute value of the result:
Depth of the well = 56.90439 meters

Therefore, the depth of the well is approximately 56.90 meters.