A stone is dropped in water from a bridge 44 cm above the water. Another stone is thrown straight down 1.0 s after the first one dropped. Both strike the water at the same time. What was the initial speed of the second stone?

Answer 1

first stone: .44=1/2 g t^2
second stone: .44=v(t-1)+1/2 g (t-1)^1

use equation 1) TO solve for t, then put it in equation 2) and solve for v.

Answer 2

who was the father of physics

Answer 3

Galileo Galilei