a) distance = -4.9t^2 + 200
b) when it hits the ground, distance = 0
4.9t^2 = 200
t = √(200/4.9) = ....
d(distance)/dt = -9.8t
plug in your value of t
c) change the equation to
distance = -4.9t^2 - 2t + 200
solve using the quadratic formula
A stone is dropped from the upper observation deck of a tower, 200 m above the ground. (Assume g = 9.8 m/s^2.)
a)Find the distance (in meters) of the stone above ground level at time t.
b)With what velocity does it strike the ground? (Round your answer to one decimal place.)
c)If the stone is thrown downward with a speed of 2 m/s, how long does it take to reach the ground? (Round your answer to two decimal places.)
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