a stone is dropped from the top of the cliff. It is seen to hit the ground below after 3.50s. How high is the cliff(60.0m)

Answer 1

well using conservation of energy calculate the speed at the bottom assuming average speed is half the speed at the ground.
(1/2) m Vg^2 = m g Hi
and
Va t = Hi = (Vg/2) t so Vg = 2 Hi /t
then
(1/2) 4 Hi^2/t^2 = g Hi
Hi = g t^2/2 = 9.81 (3.5)^2 / 2 = 60.1 meters
OR
v = -g t
h = Hi - (1/2) g t^2
0 = Hi - (1/2)(9.81)(3.5)^2 again

Answer 2

F