hf=hi+vi*t-1/2 g t^2
-2=0+vi*.2-4.8 (.2^2)
so solve for vi, the velocity at the top of the windown. Then,
vf^2=2gh where h is the distance to the roof from the top of windown. Vf is the vi you found above. Solve for h.
A stone is dropped from the root of a building. A person in the building observes that the stone
crosses his window that is 2 meters tall in a time of 0.2 second. How far is the roof from the top of
the window?
1 answer