A stone is dropped from peak of the hill. It covers a distance of 30 metres in the last second of its motion. Find the height of the peak?

Answer 1

h1 = V*t + 0.5g*t^2 = 30 m.
V*1 + 4.9*1^2 = 30
V = 30 - 4.9 = 25.1 m/s

h = (V^2-Vo^2)/2g + h1
h = (25.1^2-0)/19.6 + 30 = 62.14 m. = Ht. of the peak.