A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.
4 answers
h= h₁ - h₂= gt²/2- 100=9.8•5²/2 -100=122.5 – 100 = 22.5m
timetodrop=distance/avgspeed
avg speed=1/2 vf=1/2 at
timeto derop=(100m+d)/(1/2 9.8 *t)
5*(4.9*5)=(100+d)
d=4.9*25 -100
avg speed=1/2 vf=1/2 at
timeto derop=(100m+d)/(1/2 9.8 *t)
5*(4.9*5)=(100+d)
d=4.9*25 -100
22.5
distance= 1/2*gravity*time^2-total distance
d=1/2*9.8*5^2-100
d=22.5
d=1/2*9.8*5^2-100
d=22.5
2 answers