A stone is dropped from a hot air balloon that is rising at a constant speed of 2.2 m/s. If the stone takes 4.8 seconds to reach the ground then …

a) What was the height of the balloon at the moment the stone was released?

b) What is the height of the balloon at the time the stone hit the ground?

1 answer

hf=0=hi+vi*t-1/2 g t^2
you are given vi, and time t.
solve for initial height hi

hf=hi+2.2*4.8 use hi form above, solve for hf the final height of the balloon at time of stone crash.