A stone is aimed at a cliff of height h with an initial speed of v = 56.0 m/s directed 65.0° above the horizontal, as shown in the Figure below by the arrow. The stone strikes at A, 9.20 s after launching. What is the height of the cliff?

Answer 1

u=0,theta=65 degrees, t=9.20s
h= (u^2*sin^2theta)/(2*g)

solve this and get h..