d = Vo*t + 0.5g*t^2 = 36 Ft.
0 + 16t^2 = 36,
t^2 = 24.42,
t = 4.94 s. = Time required for stone to hit ground.
d = V*t,
V = d / t 50/4.94 = 10.1 Ft/s.
a stone falls from a rail road overpass which is 36ft. high into the path of the train which is approaching the overpass with the uniform speed, if the stone falls when the train is 50ft. away from the overpass and the stones hits the ground just as the train arrives at the spot. how fast is the train moving?
2 answers
Correction: t^2 = 36/16 = 2.25,
t = 1.5 s.
V = d / t = 50/1.5 = 33.33 Ft/s.
t = 1.5 s.
V = d / t = 50/1.5 = 33.33 Ft/s.
5 answers