A stock solution was prepared by dissolving exactly 0.4000 g of pure ASA (180.16 g/mol)
in 10.00 mL of NaOH and heating the solution to a gentle boil. After cooling to room temperature, the solution was poured into a 250-mL volumetric flask and diluted to the mark with DI water. Before coming to lab, calculate the concentration of ASA in the flask.
1 answer
None of the ASA is boiled away, presumably. Therefore you have 0.4000 g of ASA in 250 mL of liquid solution. With the molecular weight that was given, you can convert that to molarity (moles per liter)
1 answer