A steel spacer ring 0.2 m thick has an diameter of 1.5 m and an inside diameter of 1.3 m. calculate the volume of steel required to manufacture this ring

Answer 1

First, we need to calculate the volume of the entire ring by subtracting the volume of the smaller circle from the volume of the larger circle.

Volume of the larger circle = πr^2h
where r = radius of the larger circle = diameter/2 = 1.5m/2 = 0.75m
h = thickness = 0.2m

Volume of the larger circle = π(0.75)^2(0.2) = 0.3524 m^3

Volume of the smaller circle = πr^2h
where r = radius of the smaller circle = diameter/2 = 1.3m/2 = 0.65m
h = thickness = 0.2m

Volume of the smaller circle = π(0.65)^2(0.2) = 0.2694 m^3

Volume of steel required = Volume of the larger circle - Volume of the smaller circle
= 0.3524 m^3 - 0.2694 m^3
= 0.083 m^3

Therefore, the volume of steel required to manufacture this ring is 0.083 cubic meters.