A steel cylinder has a base with a radius of 10 cm and height of 8 cm. If the density of the cylinder is 8,000 kg/m3

8
,
000

kg
/
m
3
, find the mass of the cylinder in kilograms. Use π=3.14
𝜋
=
3.14
and round your answer to the nearest tenth.

1 answer

To find the mass of the steel cylinder, we can use the following steps:

  1. Calculate the volume of the cylinder using the formula: \[ V = \pi r^2 h \] where:

    • \( r \) is the radius of the base,
    • \( h \) is the height of the cylinder.
  2. Convert the radius and height from centimeters to meters:

    • Radius \( r = 10 \) cm = \( 0.10 \) m,
    • Height \( h = 8 \) cm = \( 0.08 \) m.
  3. Substitute the values into the volume formula: \[ V = \pi (0.10)^2 (0.08) \] \[ = 3.14 \times 0.01 \times 0.08 \] \[ = 3.14 \times 0.0008 \] \[ = 0.002512 \text{ m}^3 \]

  4. Calculate the mass using the formula: \[ \text{mass} = \text{density} \times \text{volume} \] Given that the density of the steel cylinder is \( 8,000 \) kg/m³: \[ \text{mass} = 8,000 \text{ kg/m}^3 \times 0.002512 \text{ m}^3 \] \[ = 20.096 \text{ kg} \]

  5. Round the answer to the nearest tenth:

    • The mass of the cylinder is approximately \( 20.1 \) kg.

Therefore, the mass of the cylinder is 20.1 kg.