A steel container of oxygen has a volume of 20.0 L at 22 C @35 atm. What is the volume @ STP? How many mol of oxygen are in the container?

Answer 1

P1V1/T1=P2V2/T2 solve for V2

Now, now many moles...

PV=nRT solve for n OR, when you solve for volume at stp, divide by 22.4liters

Answer 2

i got the answer, 2.37L..and 28.90 mol.. but that doesnt seem right to me, wouldnt it be the other way around?

P1V1/T1= 2.37 L
n=PV/RT= 28.90 mol

or should they be switched?