σ=Eε,
W/A= Eε,
ε=W/AE,
Energy=E ε²/2 = E W²/2A²E²=
= W²/2A²E=
=(30000)²/2•(1200•10⁻⁶)²•210•10⁹=
=1.49•10³ J.
A steel cable of length 10 m and cross-sectional area 1200 mm2 is loaded with an object of weight 30 kN. Given that the cable is not loaded beyond its proportional limit and Young's modulus of steel is 210 GPa, draw a stress-strain curve for the loaded cable and shade in the area which indicates the strain energy stored per unit volume, and calculate the strain energy stored by the cable.
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