L = 40 + 12*10^-6/Co(T-20) = 40.01.
40 + 12*10^-6T - 240*10^-6 = 40.01.
40 - 0.00024 + 12*10^-6T = 40.01.
39.99976 + 12*10^-6 = 40.01.
12*10^-6T = 40.01 - 39.99976 = 0.01024.
T = 853.333 Degrees C.
A steel bar has an initial length of 40 meters when the temperature is 20 oC. At what final
temperature will the steel bar have a final length of 40.01 meters? The coefficient of linear expansion of steel is 12E-6 (1/C).
1 answer