A steel ball with mass 40.0 g is dropped from a height of 2.00 m onto a

Question

horizontal steel slab. The ball rebounds to a height of 1.60 m. Calculate the
impulse delivered to the ball during impact�

Answer 1

The change in momentum of the ball during impact can be calculated using the equation:

Impulse = mass * (final velocity - initial velocity)

First, we need to calculate the initial velocity of the ball before impact. We can use the kinematic equation:

v^2 = u^2 + 2as

where:
v = final velocity after rebounding = 0 m/s (at the highest point)
u = initial velocity before impact
a = acceleration due to gravity = 9.81 m/s^2
s = height of drop = 2.00 m

0 = u^2 + 2 * 9.81 * 2.00
0 = u^2 + 39.24
u^2 = -39.24
u = sqrt(39.24) = 6.27 m/s

Now we can calculate the impulse delivered to the ball during impact:

Impulse = 0.040 kg * (0 m/s - 6.27 m/s)
Impulse = 0.040 kg * (-6.27 m/s)
Impulse = -0.25 N*s

The negative sign indicates that the impulse is in the opposite direction of the initial motion of the ball.