Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
95% = mean ± 1.96 SEm
SEm = SD/√n
I'll let you do the calculations.
A statistic instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags.They weighed 10.4, 10.9 , 10.8, and 9.9 pounds.assume that the distribution of the weights is normal. Find a 95% confidence interval for the mean weight of all bags of oranges.
2 answers
i don't knoe