A stationary roller coaster at the top of its path is 30m about the ground. The car and its passengers have a mass of 400kg. What is the velocity of the car when it reaches the ground lever? The formula for velocity is (Distance/time)

Answer 1

the gain in Kinetic energy is equal to the loss of potential energy

1/2 m v^2=mgh
solve for v

Answer 2

mass cancels out, irrelevant

m g h = (1/2) m v^2

2 g h = v^2

v = sqrt (2 g h)

v = sqrt (2*9.8*30)

v = 24.2 m/s