A stationary 1.67 kg object is struck by a stick. The object experiences a horizontal force given b F = at-bt^2, where t is the time in milliseconds from the instant the stick first contacts the object. If a = 1500 N/ms and b = 20N/ms^3, what is the speed of the object just after it comes away from the stick (t=2.74ms)?

Answer 1

Based upon the dimensions of b and the value of t when the object comes away, I believe you have copied the problem incorrectly. It should be

F = at-bt^3

in which case F = 0 at t = 2.74 ms

Integrate F dt from t=0 to t=2.74 ms

Express the answer in Newton*seconds
(not Newton*milliseconds)

That will equal the momentum of the released ball.

Use that and the mass to get the velocity.

Answer 2

20

Answer 3

3.29