Q1:
First, we need to calculate the number of moles of Na2CO3 in 5.03g.
Molar mass of Na2CO3 = 2(23) + 12 + 3(16) = 106g/mol
Number of moles = 5.03g / 106g/mol = 0.0474 moles
Therefore, the amount of Na2CO3 in moles is 0.0474 moles.
Q2:
Now, we need to calculate the concentration in moles per liter (mol/L).
Volume = 250.0 ml = 0.25 L
Concentration = amount of Na2CO3 in moles / volume in liters
Concentration = 0.0474 moles / 0.25 L = 0.1896 mol/L
Therefore, the concentration of the standard solution of Na2CO3 is 0.1896 mol/L.
A standard solution of sodium carbonate(NaCO3) is prepared by discovering 5.03g of Na2CO3 in water to give a volume of 250.0 ml 1 mole of Na2CO has a mass of 106.0g.
Q1.calculate the amount of NaCO3 in moles.
Q2.calculate the concentration in moles per liter (moiL-1).
1 answer
1 answer