To solve this problem, we first need to determine the probabilities of events A and B, and then calculate \( P(A \cap B) \), the probability of both events occurring.
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Calculating \( P(A) \):
- Event A: Choosing a black card.
- In a standard deck of 52 cards, there are 26 black cards (13 clubs and 13 spades).
- Therefore,
\[ P(A) = \frac{\text{Number of black cards}}{\text{Total number of cards}} = \frac{26}{52} = \frac{1}{2}. \]
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Calculating \( P(B) \):
- Event B: Choosing a king.
- In a standard deck, there are 4 kings (one from each suit).
- Thus,
\[ P(B) = \frac{\text{Number of kings}}{\text{Total number of cards}} = \frac{4}{52} = \frac{1}{13}. \]
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Calculating \( P(A \cap B) \):
- Event \( A \cap B \): Choosing a card that is both black and a king.
- There are 2 black kings (the king of clubs and the king of spades).
- Therefore,
\[ P(A \cap B) = \frac{\text{Number of black kings}}{\text{Total number of cards}} = \frac{2}{52} = \frac{1}{26}. \]
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Calculating \( P(A) \cdot P(B) \):
- Now we can calculate \( P(A) \cdot P(B) \):
\[ P(A) \cdot P(B) = \left(\frac{1}{2}\right) \cdot \left(\frac{1}{13}\right) = \frac{1}{26}. \]
- Now we can calculate \( P(A) \cdot P(B) \):
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Determining independence:
- Events A and B are independent if
\[ P(A \cap B) = P(A) \cdot P(B). \] - We calculated:
\[ P(A \cap B) = \frac{1}{26} \text{ and } P(A) \cdot P(B) = \frac{1}{26}. \] - Since these are equal, events A and B are independent.
- Events A and B are independent if
Summary of Results:
- \( P(A) \cdot P(B) = \frac{1}{26} \)
- \( P(A \cap B) = \frac{1}{26} \)
- Events A and B are independent.