To find \( P(A \text{ and } B) \), \( P(A) \), and \( P(B) \), we first define the events:
- Event \( A \): Choosing a red card.
- Event \( B \): Choosing an ace.
Step 1: Calculate \( P(A) \)
There are 26 red cards in a standard deck (13 diamonds and 13 hearts). Hence, the probability of event \( A \) is:
\[ P(A) = \frac{\text{Number of red cards}}{\text{Total number of cards}} = \frac{26}{52} = \frac{1}{2} \]
Step 2: Calculate \( P(B) \)
There are 4 aces in a standard deck (one from each suit). Thus, the probability of event \( B \) is:
\[ P(B) = \frac{\text{Number of aces}}{\text{Total number of cards}} = \frac{4}{52} = \frac{1}{13} \]
Step 3: Calculate \( P(A \text{ and } B) \)
Event \( A \) and event \( B \) intersect when you choose a red ace. There are 2 red aces in the deck: the Ace of Hearts and the Ace of Diamonds. Therefore:
\[ P(A \text{ and } B) = \frac{\text{Number of red aces}}{\text{Total number of cards}} = \frac{2}{52} = \frac{1}{26} \]
Step 4: Check Independence of Events A and B
Events A and B are independent if:
\[ P(A \text{ and } B) = P(A) \times P(B) \]
Calculating \( P(A) \times P(B) \):
\[ P(A) \times P(B) = \left(\frac{1}{2}\right) \times \left(\frac{1}{13}\right) = \frac{1}{26} \]
Since \( P(A \text{ and } B) = P(A) \times P(B) \), we conclude that events A and B are independent.
Final Answers:
- \( P(A \text{ and } B) = \frac{1}{26} \)
- \( P(A) = \frac{1}{2} \)
- \( P(B) = \frac{1}{13} \)
Thus, the events A and B are independent.