A standard deck of cards contains 52 cards. Of these cards there are 13 of each type of suit (hearts, spades, clubs, diamonds) and 4 of each type of rank (A – K). Two cards are pulled in order, without replacement from this deck of 52 playing cards. What is the probability that the cards will be an 8 of hearts and then an Ace?

asked by Alex

10 years ago

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1 answer

You want the 8 of hearts, then an Ace
prob = (1/52)(4/51) = 1/663

answered by Reiny

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Question

A standard deck of cards contains 52 cards. Of these cards there are 13 of each type of suit (hearts, spades, clubs, diamonds) and 4 of each type of rank (A – K). Two cards are pulled in order, without replacement from this deck of 52 playing cards. What is the probability that the cards will be an 8 of hearts and then an Ace?

1 answer

You want the 8 of hearts, then an Ace
prob = (1/52)(4/51) = 1/663

Ask a New Question or answer this question.

Reiny · Accepted Answer

You want the 8 of hearts, then an Ace prob = (1/52)(4/51) = 1/663