A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards.

Express your answer in percent form rounding to the nearest hundredth. (1 point)

1 answer

The probability of drawing a diamond on the first draw is 13/52 (since there are 13 diamonds out of 52 cards).

After drawing a diamond on the first draw, there would be 12 diamonds left and 51 total cards left. Hence, the probability of drawing a diamond on the second draw, given that a diamond was drawn on the first draw, is 12/51.

Multiplying these probabilities together gives us:

(13/52) * (12/51) = 156/2652 ≈ 0.0588

Converting to percent form and rounding to the nearest hundredth gives us 5.88%.

Therefore, the probability of drawing two diamond cards is 5.88%.