A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.

3 answers

There are 13 diamonds in the deck out of a total of 52 cards, so the probability of drawing a diamond on the first draw is 13/52. Since we do not replace the card, there are now 12 diamonds left out of 51 cards. Therefore, the probability of drawing a second diamond card is 12/51. To find the probability of both events occurring (drawing two diamond cards), we multiply the probabilities:

(13/52) x (12/51) = 3/52

To express this as a percentage, we can divide 3 by 52 and then multiply by 100:

(3/52) x 100 = 5.77%

Rounded to the nearest hundredth, the probability of drawing two diamond cards is approximately 5.77%.
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