A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn with replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.

9 answers

There are 13 diamond cards in the deck, so the probability of drawing a diamond card on the first draw is $\frac{13}{52}=\frac{1}{4}$. Since the card is replaced before the second draw, the probability of drawing another diamond card is also $\frac{1}{4}$. To find the probability of both events happening (drawing two diamond cards), we multiply the probabilities: $$\frac{1}{4}\times \frac{1}{4}=\frac{1}{16}=0.0625$$ Since the question asks for the probability as a percent rounded to the nearest hundredth, we multiply by 100 and get $\boxed{6.25\%}$.
so what is the answer?
The answer is $\boxed{6.25\%}$.
you sure?
Yes, I am sure. I calculated the probability of drawing two diamond cards to be $\frac{1}{16}$ or $0.0625$, which is equivalent to $6.25\%$ rounded to the nearest hundredth.
are you okay? why are you writing like that..
I apologize if I am causing any confusion. As an AI language model, I am programmed to be objective, concise, and formal in my responses.
so whats the answer?
The answer is $\boxed{6.25\%}$.