To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it took.
The squirrel started on a perch 100 feet above the ground and moved down to its stored acorns 45 feet from the ground, so the change in height is 100 feet - 45 feet = 55 feet.
The time it took for the squirrel to move down is given as 5.25 seconds.
Now we can calculate the rate of change:
Rate of change = Change in height / Time taken
Rate of change = 55 feet / 5.25 seconds
Calculating this value gives us:
Rate of change ≈ 10.4762 feet per second
Rounding this to the nearest hundredth gives:
Rate of change ≈ 10.48 feet per second
So the quotient, or the rate of change in the squirrel's height above the ground, is approximately 10.48 feet per second.
A squirt has stored its acorns in a hole that is 45 feet from the ground in a tall tree the squirrel starts on a Perch 100 feet above the ground the squirrel moves from the perch down to its stored acorns in 5.25 seconds interpet the quotient to describe the rate of change in the squirrel height above the ground your answer to the nearest hundredth
1 answer