Let's solve each question one by one.
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Squirrel's Rate of Change in Height:
- The squirrel starts at 100 feet and ends at 45 feet. The total change in height is: \[ \text{Change in height} = 100 , \text{feet} - 45 , \text{feet} = 55 , \text{feet} \]
- The time taken is 5.25 seconds. So, the rate of change of height is: \[ \text{Rate of change} = \frac{\text{Change in height}}{\text{Time}} = \frac{-55 , \text{feet}}{5.25 , \text{seconds}} \approx -10.48 , \text{feet/second} \]
Therefore, the answer is -10.48 feet/second.
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Dolphin's Average Rate of Change in Position:
- The dolphin jumps to 3.5 meters above and dives to 10 meters below sea level. The total change in position from the highest point to the lowest point is: \[ \text{Change in position} = 3.5 , \text{meters} - (-10 , \text{meters}) = 3.5 + 10 = 13.5 , \text{meters} \]
- The time taken for this change is 12.5 seconds. So, the average rate of change is: \[ \text{Rate of change} = \frac{13.5 , \text{meters}}{12.5 , \text{seconds}} = 1.08 , \text{meters/second} \]
Thus, the answer is 1.08 meters/second.
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Scuba Diver's Rate of Change in Depth:
- The diver goes from 15 meters below the surface to 25 meters below (since 10 meters lower means adding 10 to the initial 15 meters). So the change in depth is: \[ \text{Change in depth} = -25 , \text{meters} - (-15 , \text{meters}) = -25 + 15 = -10 , \text{meters} \]
- The time taken for this descent is 10.1 seconds. Therefore, the rate of change in depth is: \[ \text{Rate of change} = \frac{-10 , \text{meters}}{10.1 , \text{seconds}} \approx -0.99 , \text{meters/second} \]
Hence, the answer is -0.99 meters/second.
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Car's Value Decrease per Month:
- If the car's value decreases by $4,000 in the first 12 months, the monthly decrease is: \[ \text{Monthly decrease} = \frac{-4,000}{12} \approx -333.33 \]
Thus, the answer is -$333.33.
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Hikers' Water Consumption:
- If hikers are recommended to drink 24 ounces an hour, then in 10 minutes (which is \(\frac{1}{6}\) of an hour), the change in the amount of water is: \[ \text{Change in water} = 24 , \text{ounces} \times \frac{1}{6} = 4 , \text{ounces} \]
- Therefore, in a 10-minute period, the amount of water should decrease by 4 ounces.
The answer is -4 ounces because the amount in the canteen changes downwards.
Here's a summary of the answers:
- -10.48 feet/second
- 1.08 meters/second
- -0.99 meters/second
- -$333.33
- -4 ounces