To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took for the squirrel to make that change.
Change in height = 100 feet (starting height) - 45 feet (final height) = 55 feet
Time taken = 5.25 seconds
Rate of change in height = Change in height / Time taken
Rate of change in height = 55 feet / 5.25 seconds
Rate of change in height ≈ 10.48 feet/second
Therefore, the quotient, 10.48, represents the rate of change in the squirrel's height above the ground. This means that on average, the squirrel is moving downwards at a rate of approximately 10.48 feet per second.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth. please explain how you got the answer
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