A squirrel has stored it acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe rate of change in the squirrels height above the ground. Give your answer to the nearest hundredth

1 answer

To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it takes to make the change.

The change in height is from 100 feet to 45 feet, which is a decrease of 100 - 45 = 55 feet.

The time it takes for the squirrel to make this change is 5.25 seconds.

To find the rate of change, we divide the change in height by the time it takes: 55 feet / 5.25 seconds =~ 10.48 feet/second.

Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second.