let the radius be r
then the area of one of the sectors would simply be 1/4 of the area of the circle,
which would be (1/4)πr^2 or πr^2/4
A square with sides of is inscribed in a circle. What is the area of one of the sectors formed by the radii to the vertices of the square?
3 answers
if the sides are each 6 of the square then how would you find the segment?
The 6 is the hypotenuse of a right-angled triangle with the other sides as the radius
r^2 + r^2 = 36
r^2 = 18
r = √18
sector = (1/4)π(√18)^2 = 9π/2
r^2 + r^2 = 36
r^2 = 18
r = √18
sector = (1/4)π(√18)^2 = 9π/2