b×h (1/2)
7×14(1/2)
98(1/2
A=49
Perimeter= 7+14+14=35
A square which is 7 inches on a side is removed from a triangle which is a base and height of 14 inches. What is the area of the remaining region?
2 answers
There appears to be a typo in your problem. So I'm assuming b = h = 14 in.
At = bh/2 = 14*14/2 = 98 in^2 = Area of
triangle.
As = 7^2 = 49 in^2 = Area of the square.
Ar = At-As = 98 - 49 = 49 in^2 = Area
remaining.
At = bh/2 = 14*14/2 = 98 in^2 = Area of
triangle.
As = 7^2 = 49 in^2 = Area of the square.
Ar = At-As = 98 - 49 = 49 in^2 = Area
remaining.
1 answer