at half its height, all linear dimensions are also half their original values.
So, the base of the empty pyramid is 1/4 the base of the whole pyramid.
empty volume is thus (B/4)*(h/2) = Bh/8 = 40
a square pyramid resting on its base is filled to half its height with 320 cm^3 water. how much water is needed to finish filling the pyramid?
2 answers
I misread the problem. I was thinking the original volume was 320.
Instead, 320 is 7/8 of the original volume, so we still need 1/8 of the original volume to finish filling it. That is 1/7 of what was already used, or 320/7 = 45.7 cm^3
Instead, 320 is 7/8 of the original volume, so we still need 1/8 of the original volume to finish filling it. That is 1/7 of what was already used, or 320/7 = 45.7 cm^3