Make a sketch.
Did you notice that the diameter of the circle is the diagonal of the square?
area of circle = πr^2
πr^2 = 144π
r^2 = 144
r = 12 , so the diameter = 24
let each side of the square be x
then x^2 + x^2 = 24^2
2x^2 = 576
x^2 = 288
x = √288 = 12√2
perimeter = 4x = 4(12√2) = 48√2
A square is inscribed in a circle. If the area of the circle is 144(pi)cm*squared* --sorry the square root thing isnt showing up. Then the exact perimeter of the square is...
I really don't get how to solve this, but the answer is supposed to somehow be 48V2 cm
1 answer