Asked by Gem
A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and BC = 9.
I tried to approach this by finding the hypotenuse, which i found was 10, then i used that to find the area of the square which was 100, this was wrong. Then i went and did the same process with 11 and 121, but it was also wrong. What did i do wrong, and what should i be doing instead?
I tried to approach this by finding the hypotenuse, which i found was 10, then i used that to find the area of the square which was 100, this was wrong. Then i went and did the same process with 11 and 121, but it was also wrong. What did i do wrong, and what should i be doing instead?
Answers
Answered by
Reiny
First of all , the length of the hypotenuse is not 10
AC^2 = 5^2 + 9^2 = 106
So AC = √106
Area of square on that side = AC*AC = AC^2 = 106
- end of problem!
Since I don't see your diagram, I have no idea where your 11 and 121 comes from.
AC^2 = 5^2 + 9^2 = 106
So AC = √106
Area of square on that side = AC*AC = AC^2 = 106
- end of problem!
Since I don't see your diagram, I have no idea where your 11 and 121 comes from.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.