First of all , the length of the hypotenuse is not 10
AC^2 = 5^2 + 9^2 = 106
So AC = √106
Area of square on that side = AC*AC = AC^2 = 106
- end of problem!
Since I don't see your diagram, I have no idea where your 11 and 121 comes from.
A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and BC = 9.
I tried to approach this by finding the hypotenuse, which i found was 10, then i used that to find the area of the square which was 100, this was wrong. Then i went and did the same process with 11 and 121, but it was also wrong. What did i do wrong, and what should i be doing instead?
1 answer
2 answers