To find the electric field produced by the charged square conducting slab, we can use the formula for electric field produced by a uniformly charged flat sheet:
E = σ / (2 * ε₀)
where E is the electric field, σ is the charge density (charge per unit area) and ε₀ is the vacuum permittivity constant (≈ 8.854 × 10^(-12) C²/N·m²).
First, let's find the charge density, σ.
The charge on the square slab is Q = 89 µC = 89 × 10^(-6) C, and the area of the slab is A = 7 * 7 = 49 m².
So, the charge density is:
σ = Q / A = (89 × 10^(-6) C) / (49 m²) ≈ 1.8163 × 10^(-6) C/m²
Now, we can find the electric field using the formula:
E = σ / (2 * ε₀) ≈ (1.8163 × 10^(-6) C/m²) / (2 * 8.854 × 10^(-12) C²/N·m²) ≈ 102,528 N/C
Thus, the electric field produced by the charged square conducting slab is approximately 102,528 N/C.
A square conducting slab with 7 m sides carries a net charge of 89 mu or micro CC.
what is the electric field?
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