The volume of a pyramid is given by the formula V = (1/3) * base_area * height.
The base area of the original pyramid is 8 cm * 8 cm = 64 cm^2.
The volume of the original pyramid is V1 = (1/3) * 64 cm^2 * 12 cm = 256 cm^3.
The base area of the removed pyramid is 8 cm * 8 cm = 64 cm^2.
The volume of the removed pyramid is V2 = (1/3) * 64 cm^2 * 6 cm = 128 cm^3.
The volume of the truncated pyramid is V1 - V2 = 256 cm^3 - 128 cm^3 = 128 cm^3.
A square based pyramid has a base of side 8 cm and a height of 12cm. A square-based pyramid of height 6 cm is removed by cutting parallel to the base. Calculate the volume of the truncated pyramid?
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